Concordia and Mcgill engineering admission

Canadian Universities Forum (discussion group)


 
 
Subject: Concordia and Mcgill engineering admission
standards for Cegep applicants:

Concordia University:

Mechanical, software, electrical,industrial, computer engineering:

R score of 24

Civil engineering and building engineering:

R score of 22

-------------------------------

Mcgill University:

Engineering
Bioresource, Chemical; Civil; Mining (Co-op); Materials (Co-op)
Cote R
Cote R Math/Science
25.0
25.0
Mechanical
Cote R
Cote R Math/Science
27.0
27.0
Computer, Electrical, Software
Cote R
Cote R Math/Science
26.0
26.0


----------------------------

IN conclusion, Mcgill has higher standards than Concordia but not by alot.


[21-02-2006,17:39]
Anonymous
(in reply to: Concordia and Mcgill engineering admission)
You need an R score of 28 to get into science college at concordia.

https://welcome.concordia.ca/concordia/frame.jsp?url=http://registrar.concordia.ca/waa/browse/browse.html


[21-02-2006,17:45]
Anonymous
(in reply to: Concordia and Mcgill engineering admission)
You need an R score of 30 to get into Actuarial maths + interview.


[21-02-2006,17:46]
Anonymous
(in reply to: Concordia and Mcgill engineering admission)
R-score reqs change all the time, almost every year. admission reqs go up and down depending on demand and other factors. For example in 2003 you needed a 28.5 for mechanical, 28 for electrical, computer, software. But again, these change regularly. These are cote-r numbers for Quebec students only.

http://www.ecs.qc.ca/advising/images/mcgill_admissions2003.pdf

But even today
26, 25 VS 22
27 VS 24 is a substantial difference

[21-02-2006,18:15]
Anonymous
(in reply to: Concordia and Mcgill engineering admission)
24 instead of 26, wow!!

Shocking!

Your figures for 2003 are no good. You know it and I know it. They are inflated because of double cohort.


[21-02-2006,19:04]
Anonymous
(in reply to: Concordia and Mcgill engineering admission)
it´s a substantial difference, to put it in perspective, look at a 2 point difference in the 30´s
32 VS 30
or a 4 point difference
34 VS 30

there is a clear difference

What ontario double cohort? Like i said in the previous post, cote-r reqs are for Quebec students only. And if there was such a huge inflation, then why is diatetics, dentistry and law easier to get into in 2003. And why do architecture, science, agric. sciences, med, nursing, occup. therapy, physical therapy, etc. have the same reqs as today?
I can´t find the 2002 or 2004 reqs, but if you can find them, you´ll see that in 2002, you needed a 30.5 to get into comp or electr. in 2004, you needed a 29 to get into mech.
But the reqs change, like i keep saying, due to demand and other factors. A concordia representative said this to me himself when i asked him about cote-r fluctuations.

[21-02-2006,19:22]
Anonymous
You are so full of shit, you Mcgill chimp (in reply to: Concordia and Mcgill engineering admission)
Don´t you have some naked parties to attend?

http://www.ecs.qc.ca/advising/images/mcgill_admissions2003.pdf

http://upload.mcgill.ca/counsellors/CRCInfoEng04-05Rev.pdf

For medicine it did not change and for dentistry it went up over the years for god knows what reason. The fact of the matter is: for the majority of disciplines (the very popular ones) the R score requirements were higher in 2003. This was the case for management, engineering, science and arts (which make up the bulk of enrollment). why did it go up?

If you look closely, the only discipline for which the admission standards did go up from 2003 is Dentistry and human nutrition for which the applicant pool is very small from CEgep. Like I said before, for the more popular fields like management, engineering, science and arts had higher admission standards. The only possible reason for this is for some factor external to Quebec (like double cohort in ONtario). IT has nothing to do with increased popularity for management or engineering studies nor should it have anything to do with higher averages seeing as the R score takes into account class averages.

If you think that the guy with an R score of 24 is so incredibly dumber than the Mcgill student with an R score of 26, then you need a brain (yeah you do need one).

Now, seeing as you think you are some kind of smart kid and because I want the last word, I will scare you a little. consider the following question:

You are given 5 cards from a standard card deck. What is the probability that you get a full house? What is the probaility that you get two pairs?

Let´s see how smart you are. This is a basic combinatiorial question and being a Mcgill student, you should have no problems solving it. If you have trouble, perhaps you should email your pro or google!

:)

TATA








[21-02-2006,20:55]
Anonymous
(in reply to: Concordia and Mcgill engineering admission)
Combinatorial*


[21-02-2006,21:07]
Anonymous
(in reply to: Concordia and Mcgill engineering admission)
Law? THe admision standards went down by 0.1 because Ontario students cannot apply for law school nor can they apply for med school at Mcgill. Let´s also remember that Mcgill started using R scores only in 2002, so perhaps that had something to do with the variance.

Here are the possibilities:

A) Mcgill´s reputation is sinking in Quebec
B) Double cohort
C) some other factor that would also affect concordia´s standards as well

I do not have the admission standards for concordia in 2003. All I know is that in 2003, the average R score for co-op students admitted to the John Molson school was a 29.7. And now the R score is 28.



[21-02-2006,21:13]
Anonymous
*yawn* inferior concordian (in reply to: Concordia and Mcgill engineering admission)
to the above, average r-score and admission req are two very diff things. but wtv you say buddy, again i´ve got stuff to do, i´m sure you do too, so i´m not even gonna bother anymore.

the other guy, if it is another guy. i don´t know how you deem a program more popular, i´m quite sure there are lots of med and law applicants as these are prestigious programs. and i´ve said what i had to say about double cohort. too much repetition like always. science req is the same. you can have the final word for all i care, we´ve had a million posts of discussion that the final word is worthless anyway.

and your questions don´t scare me one bit. If you knew what program i´m in, what cegep i went to, you´d know that i´ve tackled much more complex problems. Since i´m sure you´re trying to con me into doing your assignment due next week, i´ll give the answer to the first question: [13*4C2*12*4]/[52C5] hint: choose value of pair, suits for pair in # ways, values of triplets and suits of triplets. use a similar method to find the second. there, happy? i finished half your assignment. if you want to scare me, then i suggest asking advanced linear algebra, partial diff eqns, advanced cal problems.





[21-02-2006,21:38]
Anonymous
(in reply to: Concordia and Mcgill engineering admission)
You are wrong...

Sorry, try again.


[21-02-2006,22:37]
Anonymous
alright (in reply to: Concordia and Mcgill engineering admission)

solve this:

consider two functions:

f(x) and g(x)

Find the nth derivative of h(x) = f.g(x)

:)

Prove that if f+g is continuous at x, and f is continous at x then g is continuous at x.


:)

these are not even advanced cal questions nor are they "advanced" linear algebra questions.


[21-02-2006,22:44]
Anonymous
The correct answer to my question was (in reply to: Concordia and Mcgill engineering admission)
[13*(4c3) * (12) * (4 c 2)]/[52c5]

Tsk, TSk, you suck!

I hardly think you can answer my two other easy questions.

I am not impressed!


[21-02-2006,22:46]
Anonymous
(in reply to: Concordia and Mcgill engineering admission)
sorry, but i´m 100% sure i´m correct and that you´re wrong. re-read your probability textbooks and don´t try to squeeze a full solution out of me, i´m not responsible for your assignments.

seriously, if you can´t ask a question from the topics that i´ve mentioned (since you´re just not at my level), then simply don´t ask at all. Now you´re just wasting my time with simple cal 1 theorems. Honestly, you don´t want to play this game with me, since your accounting (IF you really are in accounting ;) ) mathematics are really no comparison to what i do.

that´s all buddy, have a nice spring break. It was fun while it lasted.


[21-02-2006,23:10]
Anonymous
haha, loser! (in reply to: Concordia and Mcgill engineering admission)
Im very good at maths... (Better than you, for sure!)

Hey man, you are wrong. This is not in my prob book, its a simple question.

naturally, you must divide by 52 combination 5.

Now for the top:

What is a full house?

It is three of a kind + a pair, example:

(2,2,2) & (3,3)

You have 13 different numbers (A,2,3,4,...,King) with 4 cards from each number.

If you are looking for triplets, then you have 4c3 *13

(those are all the combinations of triplets you can produce)

Now, for the last pair. Obviously, since you already have a triplet, your pair cannot have the same number as the triplet, so you only consider 12 numbers:

12* (4c2)

Putting everything together:


[13*(4c3)*12(4c2)]/[52c5]


So easy!!

For the two pairs:

[13*[4c2] * 12 [4c2] * (52-8)]/[52c5]

Yeah, IM so smart!!

Talk about a dumb CONCOrdia student!!




[21-02-2006,23:20]
Anonymous
(in reply to: Concordia and Mcgill engineering admission)
btw
my answer: [13*4C2*12*4]/[52C5]
your answer: [13*(4c3) * (12) * (4 c 2)]/[52c5]

[13*4C2*12*4]/[52C5] = [13*(4c3) * (12) * (4 c 2)]/[52c5]
since 4C3 = 4

so i was right, like i said

[21-02-2006,23:22]
Anonymous
(in reply to: Concordia and Mcgill engineering admission)
remember when i told you to READ first, you´d notice that
4C3 = 4
therefore i was correct and we have the same answer

seriously, LOOK and READ first

[21-02-2006,23:25]
Anonymous
Calculus question? (This one is a breeze) (in reply to: Concordia and Mcgill engineering admission)
Consider the following:

x=x(t)
y=y(t)
z=z(t)

consider the function f(x,y,z):

2(x^2) + 3(z) + 4(y^2) = f(x,y,z)

Find d(f)/dt

This is easy!

I can go on and on...There are alot of things you do not know about me.

:)


[21-02-2006,23:31]
Anonymous
haha, nice try! (in reply to: Concordia and Mcgill engineering admission)
YOu just got lucky since 4c3 = 4

You wrote it up all wrong.

Why didnt you just put 4c2 = 6

?

What about the order of your multiplications? it is not logical. You write 12 * 4, when it should have been:

4 * 13 * 12 * (4c2).




[21-02-2006,23:35]
Anonymous
What are you studying at Mcgill? (in reply to: Concordia and Mcgill engineering admission)
Just curious...(Not trying to insult you here...)


[21-02-2006,23:36]
Anonymous
Hey (in reply to: Concordia and Mcgill engineering admission)
Do not bother doing the two other questions I asked you after the card question... (They are not that easy...)

I am betting you never took a course in theoretical mathematics?

the answer to the third question (The one about the nth derivative) is pretty cool. It is called the leibniz formula... (look it up). The one about continous functions is not so bad, but you need to be comfortable with delta-epsilon notation.




[21-02-2006,23:40]
Anonymous
(in reply to: Concordia and Mcgill engineering admission)
k k last post, i thought i was thru with this thread already:
i´ll set up each problem just by eyeballing:
f(x) and g(x)

Find the nth derivative of h(x) = f.g(x)

this is cal 1, since both f and g are functions wrt x, this is simple product rule (which is also called leibniz law).

Prove that if f+g is continuous at x, and f is continous at x then g is continuous at x.

this is a cal 1 proof, one can do this with limits, and the proof i´m sure is in standard calculus textbooks.

x=x(t)
y=y(t)
z=z(t)

consider the function f(x,y,z):

2(x^2) + 3(z) + 4(y^2) = f(x,y,z)

Find d(f)/dt

since x, y, and z are functions of t, but f a function of x,y,z, this is a multi-variable partial differentiation problem with chain rule. Classic cal 3.

full house (not luck, my friend):
i chose value of pair: 13C1
chose suits for pair in 4C2 ways
chose values of triplets 12C1
chose suits of triplets 4C3 = 4

the product of the above gives me the event
divide this by sample space to get probability
the 4 was put there to see if you´d actually pay attention to my post, so i gotcha there

from the questions you´ve asked me, your level is around intermediate calculus/cal 3 which is appropriate or even more than most commerce students do. you seem interested in math, you should do a math or physics major or go into engineering. beyond the intermediate level, calculus and math in general becomes very complex and abstract: computation of flux, surface integrals, curls, green´s and div theorems. Then there´s the linear algebra: using eigenvalues/vectors, tranformation matrices, etc. to solve differential equations. The use of Fourier series, especially with complex exponential functions, etc. and applying it to real world situations... And i´m sure a math major does much more than this!

very last post, i´m outta here




[22-02-2006,02:37]
Anonymous
(in reply to: Concordia and Mcgill engineering admission)
yes, you were just checking if I was reading... I guess its common knowldege that 4c3 = 4.

I am tired of bickering with you. Your answers to the other questions are not really answers, but at least you seem to know which course the material is covered in!

Take care and good luck with engineering at Mcgill (I think that is what you are studying, even though you have not actually told me).




[22-02-2006,13:22]
Anonymous
(in reply to: Concordia and Mcgill engineering admission)
wtf my head hurts pass the bong lol
[23-02-2006,17:08]
York Student



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